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### 7th 6.65

Posted: Wed Mar 13, 2019 9:14 pm
Can anyone tell me how to arrive at this answer?

### Re: 7th 6.65

Posted: Fri Mar 15, 2019 4:28 pm
Please attempt the problem, show us your work, so we can gage where you may be struggling with it.

### Re: 7th 6.65

Posted: Sat Mar 16, 2019 10:17 pm
I used $E=-\frac{RT}{NF}lnQ=-\frac{8.314\times 298.15}{1\times 96485}ln\frac{10^{-14}}{10^{-7}}\approx 0.414$. I thought Q is between 10^-7 and 10^7, but the answer seems to imply that instead it should be between 10^-14 and 10^14.