## Hw. 13.35b n as the moles of electrons

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

jpevec3F
Posts: 6
Joined: Fri Sep 26, 2014 2:02 pm

### Hw. 13.35b n as the moles of electrons

For this question, I understand how you use lnK = nEcell/(0.02596) , but for part b, I got n=1. What in the question tells you that n=2?

Niharika Reddy 1D
Posts: 127
Joined: Fri Sep 26, 2014 2:02 pm

### Re: Hw. 13.35b

n is the moles of electrons transferred, so you're right in getting 1. This problem is on the solutions manual errors document, but I believe the final answer on the corrected solutions is incorrect, although the work leading up to it is right.

jpevec3F
Posts: 6
Joined: Fri Sep 26, 2014 2:02 pm

### Re: Hw. 13.35b

That's what I did for all the other ones, so I was baffled when this came up. Thanks for the heads up!

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