6N.1b


Moderators: Chem_Mod, Chem_Admin

Alicia Lin 2F
Posts: 83
Joined: Wed Sep 18, 2019 12:17 am

6N.1b

Postby Alicia Lin 2F » Mon Feb 24, 2020 9:31 pm

In the answer key they say that the reduction half reaction involves two electrons transferred and therefore n would be equal to 2. However, shouldn't the reaction only be involving 1 electron transfer since it is going from In3+ to In2+ which would also make lnK=4.67 and K=107?

nicolely2F
Posts: 149
Joined: Sat Sep 14, 2019 12:17 am

Re: 6N.1b

Postby nicolely2F » Mon Feb 24, 2020 10:16 pm

Yeah, it's a typo. In "Corrections to Solutions Manual" it's corrected to 1 electron. The final answer's K approximately equal to 100.


Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

Who is online

Users browsing this forum: No registered users and 2 guests