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6N3.B
Posted: Wed Feb 26, 2020 9:29 pm
by Alex Tchekanov Dis 2k
Could someone please explain how we know which element is the product or reactant in this problem? I did everything correctly but instead, I put Zinc as the reactant when I solved for Q and I got the wrong answer. I assumed Zinc was the reactant because it is the anode in this equation and that's where the electrons will come from...
Re: 6N3.B
Posted: Wed Feb 26, 2020 9:57 pm
by Benjamin Feng 1B
You are right that zinc is the reactant, but that means that Zn2+ is the product, so that goes on top when calculating Q
Re: 6N3.B
Posted: Wed Feb 26, 2020 10:11 pm
by Julie_Reyes1B
For that problem, it does look like Zinc is a reactant and the zinc ion is the product. It seems like you got that part right! Maybe you made a mistake with the Q term; for that problem, make sure it is [Zn2+]/[Ni2+].
In terms of deciding which is the anode and cathode, the locations of the substances in the cell diagram will tell you. The right tends to be the cathode, and the left tends to be in the anode. If you're unsure, you can also look at the potentials and the one with a stronger reduction potential (will be reduced) will be the cathode.