6N.1 part B

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Skyllar Kuppinger 1F
Posts: 52
Joined: Thu Jul 25, 2019 12:16 am

6N.1 part B

I got part A right but part B wrong even tho I did them the exact same way. The problem said to find K. The book says the answer is 1x10^4 but I got 107. Will someone please tell me what I'm doing wrong
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Ariel Fern 2B
Posts: 105
Joined: Fri Aug 30, 2019 12:17 am

Re: 6N.1 part B

The answer in the book is a typo! In the solutions manual, they put that n = 2 moles even though it should only be 1 mole of electrons. By using 1 mole, you get the correct answer of K = 1 x 102 rather than K = 1 x 104! Hope this helps!

Skyllar Kuppinger 1F
Posts: 52
Joined: Thu Jul 25, 2019 12:16 am

Re: 6N.1 part B

Ariel Fern 2B wrote:The answer in the book is a typo! In the solutions manual, they put that n = 2 moles even though it should only be 1 mole of electrons. By using 1 mole, you get the correct answer of K = 1 x 102 rather than K = 1 x 104! Hope this helps!

Thank you so much!!! I lost my solutions manual so I didn't notice that !!

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