## 6N 9: anode v cathode

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Siddiq 1E
Posts: 106
Joined: Fri Aug 09, 2019 12:15 am

### 6N 9: anode v cathode

Hi, for the question 6N.9, I don't understand why you can assume the tin electrode is the anode?

GFolk_1D
Posts: 101
Joined: Fri Aug 09, 2019 12:15 am

### Re: 6N 9: anode v cathode

I believe if you treated it as the cathode the Ecell would be negative (which it tells you its a positive 0.061)

Hailey Kim 4G
Posts: 110
Joined: Sat Jul 20, 2019 12:16 am

### Re: 6N 9: anode v cathode

The standard reduction potential for Sn2+ + 2e- ---> Sn is -0.14V
The standard reduction potential for 2H+ + 2e- ---> H2 is 0.0V

Therefore, tin would be the anode because you would flip the sign to get a positive standard cell potential (+0.14V).

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