## text problem 6m.1

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

JosephineF
Posts: 49
Joined: Wed Sep 18, 2019 12:17 am

### text problem 6m.1

The stated short hand for the reaction in the text is $M\left | M^{+} \left \| Cu^{2+}\left | Cu$
But in the solution manual says it's $Cu\left | Cu^{2+}\left \| M^{2+}\left |M$
This affects which element is considered the anode and which is considered the cathode but I'm unclear as to why they reversed the short hand?

Paige Lee 1A
Posts: 136
Joined: Sat Sep 07, 2019 12:16 am

### Re: text problem 6m.1

I'm pretty sure the anode is supposed to be the M2+/M

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