## 6O1

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Diana_Diep2I
Posts: 130
Joined: Sat Aug 17, 2019 12:17 am

### 6O1

How come the answer key says to choose the reduction reaction with the highest standard reduction potential and to choose the oxidation reaction with the lowest reduction potential and then proceeds to do the opposite?

Ariel Davydov 1C
Posts: 110
Joined: Thu Jul 11, 2019 12:16 am
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### Re: 6O1

This occurs in this particular example because the reaction begins with Ni2+ ions. Regardless of its standard reduction potential, the reaction begins with these ions since they are already present in the solution and thus is reduced to Ni(s).

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