## 6N.15

$E_{cell} = E_{cell}^{\circ}-\frac{RT}{nF}\ln Q$

Maya Gollamudi 1G
Posts: 100
Joined: Thu Jul 25, 2019 12:15 am

### 6N.15

How do you solve problem 6N.15:
Calculate the potential of a cell constructed with two nickel electrodes. The electrolyte in one compartment is 1.0 M Ni (NO3)2. In the other compartment, NaOH has been added to a Ni(NO3)2 solution until the pH=11.0 at 298 K

Chem_Mod
Posts: 19492
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 878 times

### Re: 6N.15

You know that the redox half reactions should relate to Ni2+ + 2e- --> Ni. When you add OH- to one of the compartments, Ni2+ + 2OH- --> Ni (OH)2. Because Ni2+ ions are being used in this compartment to form Ni(OH)2, your two compartments have a different concentration of Ni2+. You can use the Nernst equation to solve for Ecell.