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calculating Q

Posted: Sun Mar 08, 2020 8:10 pm
by 805383532
When finding Q in the nernst equation, is it always [cathode]/[anode] or is it [anode]/[cathode] ?

Re: calculating Q

Posted: Sun Mar 08, 2020 8:11 pm
by Bilal Pandit 1J
It can be determined by the overall cell reaction, with the concentrations plugged in for Q (products over reactants)

Re: calculating Q

Posted: Sun Mar 08, 2020 8:20 pm
by Sjeffrey_1C
I believe its [anode]/[cathode]

Re: calculating Q

Posted: Sun Mar 08, 2020 8:20 pm
by Isabella Dal Porto 1H
I believe that it is [anode]/[cathode].

Re: calculating Q

Posted: Sun Mar 08, 2020 8:25 pm
by J_CHEN 4I
Q is [Products]/[Reactants] so it depends on the chemical equation.

Re: calculating Q

Posted: Sun Mar 08, 2020 9:13 pm
by AronCainBayot2K
Q should be anode/cathode.

Re: calculating Q

Posted: Sun Mar 08, 2020 9:14 pm
by Bryce Barbee
I was told that it is anode/cathode when using this equation.

Re: calculating Q

Posted: Sun Mar 08, 2020 9:26 pm
by saigorijavolu2k
anode/cathode

anode looses mass, cathode gains mass

Re: calculating Q

Posted: Sun Mar 08, 2020 9:28 pm
by Vivianvelazquez_1J
It should be Anode over Cathode.

Re: calculating Q

Posted: Tue Mar 10, 2020 8:27 pm
by Trent Yamamoto 2J
Q= [anode]/[cathode]

Re: calculating Q

Posted: Wed Mar 11, 2020 3:37 pm
by Sean Cheah 1E
Q is a reaction quotient, which means that for most redox reactions, as long as you have the balanced equation, it should look identical to the equilibrium expression (with appropriate exponents to match the coefficients in the balanced equation). The equilibrium expression always puts products in the numerator and reactants in the denominator.

For example, looking at the generic redox equation A+(aq) + B (s) --> A(s) + B+(aq), the only concentration on the products' side is [B+] and the only concentration on the reactants' side is [A+]. Note that in this case, A+ is the species being reduced, meaning it is being consumed like a reactant at the cathode. Similarly, B(s) is the species being oxidized, meaning B+ is being produced like a product at the anode. Thus, since the coefficients are all 1 in this case, Q = [B+]/[A+] = [Anode ion]/[Cathode ion].

Re: calculating Q

Posted: Thu Mar 12, 2020 9:24 am
by Alexandra Bartolome 2H
Q = [products]/[reactants] so it would be [anode]/[cathode]

Re: calculating Q

Posted: Thu Mar 12, 2020 9:30 am
by Mariah
I think its easier to think products/reactants.