Endgame 1a


Moderators: Chem_Mod, Chem_Admin

Michael Du 1E
Posts: 117
Joined: Sun Sep 22, 2019 12:16 am

Endgame 1a

Postby Michael Du 1E » Fri Mar 13, 2020 4:26 pm

In the review packet, 1a, what determines the fact that the lower concentration of the Ag+ (0.10M) is on the left anode side and the higher concentration (2.0 M) is in the cathode side of the concentration cell? or it doesn't matter, thanks!

MingdaH 3B
Posts: 133
Joined: Thu Jul 11, 2019 12:17 am

Re: Endgame 1a

Postby MingdaH 3B » Fri Mar 13, 2020 11:36 pm

anode is always oxidized, and the side with lower concentration will always be oxidized.

KnarGeghamyan1B
Posts: 102
Joined: Fri Aug 09, 2019 12:15 am

Re: Endgame 1a

Postby KnarGeghamyan1B » Sat Mar 14, 2020 1:32 am

Since cells flow from anode to cathode, it makes sense that the side with the lower concentration of cations will oxidize and the higher concentration will be reduced until both sides are balanced.

AlyssaYeh_1B
Posts: 100
Joined: Sat Aug 17, 2019 12:16 am

Re: Endgame 1a

Postby AlyssaYeh_1B » Sat Mar 14, 2020 2:30 pm

I believe we discussed in lecture that we should always make the lower concentration the product, so that "it is in solution", which means that the lower concentration will always be on the anode side

ValerieChavarin 4F
Posts: 99
Joined: Wed Sep 18, 2019 12:18 am

Re: Endgame 1a

Postby ValerieChavarin 4F » Sat Mar 14, 2020 3:06 pm

the anode is the side with the lower concentration as it is the side where oxidation occurs.

CNourian2H
Posts: 106
Joined: Fri Aug 30, 2019 12:16 am

Re: Endgame 1a

Postby CNourian2H » Sat Mar 14, 2020 9:14 pm

yes, just remember that the lower concentration is always in the products.


Return to “Appications of the Nernst Equation (e.g., Concentration Cells, Non-Standard Cell Potentials, Calculating Equilibrium Constants and pH)”

Who is online

Users browsing this forum: No registered users and 7 guests