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The Nernst equation is E = E(standard) - (RT/nF)lnQ. Since R = 8.314 J * K^-1 * mol^-1, it will cancel out with the units for T, temperature, at Kelvin. the mol in R will also cancel with the mol for Faraday's constant, which is C/mol. Then, what you end with for the units of (RT/nF) is J/C, which essentially equals a volt. Because lnQ has no units, you will end up with volts and E(standard) will also be in volts.
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