Textbook Problem 6N.13

[Emma Healy 2J]

Hi! When I used the Nernst Equation on Textbook Problem 6N.13, I got Q=2.67 x 10^6, but the answer key said the answer was just 10^6, and I'm not sure why the answer should just be 10^6? Thank you in advance!

6N.13 Calculate the reaction quotient, Q, for the following cell reactions, given the measured values of the cell potential. Balance the chemical equations by using the smallest whole-number coefficients.(a) Pt(s)|Sn4+(aq),Sn2+(aq)||Pb4+(aq),Pb2+(aq)|C(gr),Ecell = +1.33 V.

[Lakshmi Davuluri 1E]

Hi, I also got the same answer as you. I think the answer key must have rounded a number somewhere because I got lnQ=14.79, and they used lnQ=15. I think they just forgot to put the number before 10^6? Even if you use lnQ=15, you don't get just 10^6. Hope this helps

[Eileen Quach Dis 2A]

I got the same answer too! I think it's because they used ln instead of log.

[Eileen Quach Dis 2A]

I got the same answer too! I think it's because they used ln instead of log.

[Matlynn Giles 2E]

I am pretty sure it is because they used ln rather than using log.

[Mari Williams 1K]

Ok good I thought I was going crazy because e^15 isn't 10^6!

[306022612]

Is someone able to explain how we know to switch the reaction of SN2+ --> Sn4+ + 2e-. How did we know that that half-reaction needed to be flipped, not the other half-reaction?