Hi! When I used the Nernst Equation on Textbook Problem 6N.13, I got Q=2.67 x 10^6, but the answer key said the answer was just 10^6, and I'm not sure why the answer should just be 10^6? Thank you in advance!
6N.13 Calculate the reaction quotient, Q, for the following cell reactions, given the measured values of the cell potential. Balance the chemical equations by using the smallest whole-number coefficients.(a) Pt(s)|Sn4+(aq),Sn2+(aq)||Pb4+(aq),Pb2+(aq)|C(gr),Ecell = +1.33 V.
Textbook Problem 6N.13
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 100
- Joined: Wed Sep 30, 2020 9:50 pm
Re: Textbook Problem 6N.13
Hi, I also got the same answer as you. I think the answer key must have rounded a number somewhere because I got lnQ=14.79, and they used lnQ=15. I think they just forgot to put the number before 10^6? Even if you use lnQ=15, you don't get just 10^6. Hope this helps
-
- Posts: 199
- Joined: Wed Sep 30, 2020 9:49 pm
Re: Textbook Problem 6N.13
I got the same answer too! I think it's because they used ln instead of log.
-
- Posts: 199
- Joined: Wed Sep 30, 2020 9:49 pm
Re: Textbook Problem 6N.13
I got the same answer too! I think it's because they used ln instead of log.
-
- Posts: 104
- Joined: Wed Sep 30, 2020 10:10 pm
- Been upvoted: 1 time
-
- Posts: 104
- Joined: Wed Sep 30, 2020 9:53 pm
Re: Textbook Problem 6N.13
Is someone able to explain how we know to switch the reaction of SN2+ --> Sn4+ + 2e-. How did we know that that half-reaction needed to be flipped, not the other half-reaction?
Who is online
Users browsing this forum: No registered users and 3 guests