Textbook 6N.13


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ChihWei Chen 2C
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Joined: Wed Nov 18, 2020 12:24 am

Textbook 6N.13

Postby ChihWei Chen 2C » Thu Mar 11, 2021 8:48 pm

6N.13 Calculate the reaction quotient, Q, for the following cell reactions, given the measured values of the cell potential. Balance the chemical equations by using the smallest whole-number coefficients.
(a) Pt(s)|Sn4+(aq),Sn2+(aq)||Pb4+(aq),Pb2+(aq)|C(gr), Ecell = +1.33 V.
(b) Pt(s)|O2(g)|H+(aq)||Cr2O7−2(aq),H(aq),Cr3+(aq)|Pt(s), Ecell = +0.10 V.

Does anyone know why in the solution they used the equation E = Enaught - (0.025693V/n)lnQ instead of E = Enaught - (0.0592/n)logQ? I assumed the temperature is 298K since the question didn't really specify. Are these 2 equations the same at 298K? When I used the second equation I got 2.62 x 10^6 and the correct answer is 10^6.

Ken_Cheng_2A
Posts: 51
Joined: Wed Nov 18, 2020 12:30 am

Re: Textbook 6N.13

Postby Ken_Cheng_2A » Thu Mar 11, 2021 8:52 pm

Other people had the same question, so I think general consensus is that it's a typo, since the 10^6 part is consistent.


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