Textbook 6N.13


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Rachel Kwan 1B
Posts: 58
Joined: Wed Nov 18, 2020 12:23 am

Textbook 6N.13

Postby Rachel Kwan 1B » Sun Mar 14, 2021 7:54 am

How do you calculate Q? The answer key includes 0.0129V in the denominator but I'm not sure where that comes from. Is Q just the difference of Enaught-E/some other number?

Edit: Nevermind! I realized I am solving for Q in this question lol

Chem_Mod
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Re: Textbook 6N.13

Postby Chem_Mod » Mon Mar 15, 2021 11:27 am

Good you resolved it. :-)


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