14.101

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ClaireHW
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Joined: Fri Sep 29, 2017 7:07 am
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14.101

Postby ClaireHW » Wed Feb 21, 2018 8:09 pm

In a neuron, the concentrations of K+ ions inside the cell is about 20 - 30 times as great as that outside. What potential difference between the inside and the outside of the cell would you expect to measure if the difference is due only to the imbalance of potassium ions?

I'm confused about why E= 0V

Thanks!

(Claire Woolson Dis 1K)

Justin Chang 2K
Posts: 53
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.101

Postby Justin Chang 2K » Wed Feb 21, 2018 10:30 pm

E^o=0V because the standard potentials inside and outside the cell are the same. The reaction only involves potassium going in and out of the cell. Therefore, if you do E=E(cathode)-E(anode), you will get 0 because the same number minus the same number is 0. However, keep in mind that this is referring to the E^o of the value; the standard potential voltage. Because the concentrations are different, E will have some voltage since the concentrations are not the same. However, E^o is equal to 0.

veneziaramirez 3I
Posts: 57
Joined: Fri Sep 29, 2017 7:07 am

Re: 14.101

Postby veneziaramirez 3I » Thu Mar 15, 2018 12:22 pm

Where does the 0.0257V come from? Why isn't it 0.05916V?

Kayla Danesh 1F
Posts: 38
Joined: Thu Jul 13, 2017 3:00 am

Re: 14.101

Postby Kayla Danesh 1F » Thu Mar 15, 2018 12:48 pm

0.0257 is when you are using ln, 0.05916 is when you are using log.

April P 1C
Posts: 38
Joined: Thu Jan 12, 2017 3:01 am

Re: 14.101

Postby April P 1C » Sat Mar 17, 2018 10:15 pm

How come Q= 1/[K+]


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