14.55

Janine Chan 2K
Posts: 71
Joined: Fri Sep 29, 2017 7:04 am

14.55

The solution manual states that the cathode should have the least negative E and the anode should have the most negative E. However, it then says that the cathode, which is Ni2+, has a E of -0.23 V while the anode has a E of +1.23 V. Isn't this contradictory?

Also, if the point is to make a cell with the least negative E, does this mean that the value of E must be negative (but just not very negative) or does it just mean we want the most positive value possible?

Andy Nguyen 1A
Posts: 56
Joined: Thu Jul 27, 2017 3:00 am

Re: 14.55

The +1.23 volts is for the oxidation reaction. The standard reduction potential is actually -1.23 V so the solution manual is correct. And you want to get the most negative value of E because in an electrolytic cell, the reaction is non spontaneous.

Janine Chan 2K
Posts: 71
Joined: Fri Sep 29, 2017 7:04 am

Re: 14.55

Andy Nguyen 1A wrote:The +1.23 volts is for the oxidation reaction. The standard reduction potential is actually -1.23 V so the solution manual is correct. And you want to get the most negative value of E because in an electrolytic cell, the reaction is non spontaneous.

Thanks, I see what you mean. But if the +1.23 volts is for the oxidation reaction (aka they already made it the negative of the standard reduction potential), the equation in part c should say -0.23 + 1.23, which should give a positive voltage, right?

Andy Nguyen 1A
Posts: 56
Joined: Thu Jul 27, 2017 3:00 am

Re: 14.55

I believe you should get a positive voltage since the cell is electolytic.

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