15.3 [ENDORSED]
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Re: 15.3
In regards to the rate of formation of O2, first we find the rate of rxn for NO2 which is the change in concentration over the change in time (130 mmol x L^-1 / 20 sec) giving us 6.5 mmol/sec
The we see from the coefficients that the rate of formation of oxygen is 1/2 that of NO2, so it should be 6.5/2 = 3.3 mmol/s
The we see from the coefficients that the rate of formation of oxygen is 1/2 that of NO2, so it should be 6.5/2 = 3.3 mmol/s
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Re: 15.3
The unique average rate of the reaction uses utilizes the average rate of consumption equation with the stoichiometric coefficient in the denominator. Refer to the equation at the bottom of page 613 in the textbook.
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Re: 15.3
Regarding the first part of this problem, is there a reason why the answer book converts mmol to mol?
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Re: 15.3
In part c of this peoblem it asks what is unique about it. Could someone explain this to me.
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Re: 15.3 [ENDORSED]
In part c it is asking for the unique rate of the reaction, so you divide the rate for the certain term by its stoichiometric coefficient.
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