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k & K

Posted: Fri Mar 08, 2019 8:30 am
by Diana Sandoval 1K
What is the difference between k in kinetics and K in equilibrium/ thermo?

Re: k & K

Posted: Fri Mar 08, 2019 8:51 am
by Ray Huang 1G
k in electro should be Boltzmann's constant while k in kinetics is a number unique to each reaction scaling how quickly the reaction proceeds.

Re: k & K

Posted: Fri Mar 08, 2019 10:00 am
by Anushi Patel 1J
To add to the previous answer, K in thermodynamics is the equilibrium constant, which describes the concentrations of reactants and products at equilibrium, and doesn’t have anything to do with the speed of the reaction.

Re: k & K

Posted: Fri Mar 08, 2019 11:14 am
by Nico Edgar 4L
k is a rate constant dependent on the reaction you have. K is the equilibrium constant.

Re: k & K

Posted: Fri Mar 08, 2019 12:34 pm
by Jennifer Lathrop 1F
how do you know when to use it as a Boltzmann's constant or a rate constant?

Re: k & K

Posted: Fri Mar 08, 2019 12:34 pm
by Jennifer Lathrop 1F
or are those the same?

Re: k & K

Posted: Sat Mar 09, 2019 5:26 pm
by Gracie Ge 2E
isn't boltzmann's constant used to calculate entropy with the number of possible states of a molecule and the number of molecules?
rate constants and boltzmann are entirely different things.

Re: k & K

Posted: Sat Mar 09, 2019 11:27 pm
by Amy Dinh 1A
k is Boltzmann constant, which is equal to 1.38064852 × 10^-23 m2 kg s^-2 K^-1. K is the equilibrium constant of a reaction, which is calculated by the concentration of the products over concentration of the reactants.

Re: k & K

Posted: Sat Mar 09, 2019 11:38 pm
by Lumbini Chandrasekera 1B
k is the Boltzmann rate constant while K is the equilibrium constant for a certain reaction.

Re: k & K

Posted: Sat Mar 09, 2019 11:48 pm
by maldonadojs
I am sure the question will tell us to use the k as a rate constant in kinetics in the question, whereas the k Boltzmann constant will be used to calculate the entropy. K will be given in an acids and base question. It is based off of context.

Re: k & K

Posted: Sun Mar 10, 2019 12:44 pm
by Krista Mercado 1B
The difference is that k is Boltzmann's constant, while K is the equilibrium constant for a given reaction.

Re: k & K

Posted: Sun Mar 10, 2019 1:16 pm
by Aarti K Jain 1L
In kinetics, k is the rate constant, whereas K is the equilibrium constant. Also, K = k/k', which means the the equilibrium constant is equal to the ratio of rate constants of the forward (k) and the reverse (k') elementary reactions.

Re: k & K

Posted: Wed Mar 13, 2019 10:16 am
by allisoncarr1i
lower case k is the boltzmann constant and upper case K is the equilibrium constant

Re: k & K

Posted: Wed Mar 13, 2019 2:35 pm
by Kyither Min 2K
k is the rate constant so it's basically an indicator of how fast the reaction will happen. K is the equilibrium constant that tells you the ratio of products to reactant concentrations when the reaction is at equilibrium. Based on the relationship between k and K, we can determine that the forward reaction's rate constant, k will be larger than the reverse reaction rate constant if K (equilibrium constant) is larger than 1.

Re: k & K

Posted: Wed Mar 13, 2019 8:42 pm
by Megan_Ervin_1F
It is also important to note that K can be figured out by taking the ratio of the forward reaction K to the reverse reaction K

Re: k & K

Posted: Fri Mar 15, 2019 10:33 pm
by Melissa Villanueva1K
Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.

Re: k & K

Posted: Sat Mar 16, 2019 12:32 pm
by Ashley P 4I
Melissa Villanueva1K wrote:Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.

Do you mean on the constants and equations sheet?

Re: k & K

Posted: Sat Mar 16, 2019 2:02 pm
by Milena Aragon 2B
Melissa Villanueva1K wrote:Will there be a clear indication of 'k' and 'K' on the final? Such as bolding one over the other. Thanks.


I think in order to avoid confusion, it may be written out for us along with the variable e.g. "the rate constant, k,..."

Re: k & K

Posted: Sat Mar 16, 2019 2:23 pm
by JacobHershenhouse3G
K is the equilibrium constant and kr is the rate constant, symbolizing different constant values with different meanings, applied in different equations but they are related. K is equal to the overall forward rate constant over the reverse rate constant because at equilibrium the forward and reverse rates (not the constants) are equal.