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15.39

Posted: Tue Mar 12, 2019 7:56 pm
by kanikubari
Where did the 0.19mol come from for molB?

Re: 15.39

Posted: Tue Mar 12, 2019 8:14 pm
by Elaine Pham 2E
The molarity of B is given in the problem as 0.19.

Re: 15.39

Posted: Tue Mar 12, 2019 9:37 pm
by Vanadium Wang 4H
"(b) A -> 2B + C, when [A]0 = 0.15 mol*L-1, for the concentration of B to increase to 0.19 mol*L-1, given that k = 0.0035 L*mol-1*min-1 in the rate law for the loss of A."