Kinetics Plots
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 61
- Joined: Fri Sep 28, 2018 12:15 am
Kinetics Plots
I remember that the three plots vs time that we are working with are [A], 1/[A], and ln[A] but what does it mean if we get a straight line for each individual graph?
-
- Posts: 60
- Joined: Fri Sep 28, 2018 12:23 am
Re: Kinetics Plots
A straight line for ln(A) means the reaction is first order. For 1/A it means the reaction is second order. For A it means the reaction is zero order.
-
- Posts: 30
- Joined: Fri Sep 28, 2018 12:19 am
Re: Kinetics Plots
If it's a straight line with a negative slope then it can be zero order or first order. If the graph displays [A] vs. time with a negative slope then it's zero order and if the graph displays ln[A] vs time with a negative slope then it's a first order reaction.
A second order reaction would be plotted as 1/[A] vs. time with a positive slope.
A second order reaction would be plotted as 1/[A] vs. time with a positive slope.
-
- Posts: 59
- Joined: Fri Sep 28, 2018 12:18 am
Re: Kinetics Plots
If you plot any of those graphs but get a curve, you know you have the wrong order reaction
-
- Posts: 61
- Joined: Fri Sep 28, 2018 12:16 am
Re: Kinetics Plots
If the line is straight for a graph, then the reaction is that order. For instance if the data points give you a straight line for lnA on the y-axis and t on the x-axis, you know you have a first order reaction.
Re: Kinetics Plots
But if you have a plot of [reactant] vs time for a first order reaction then in that case you'll get an exponential curve which is decreasing.
Return to “Kinetics vs. Thermodynamics Controlling a Reaction”
Who is online
Users browsing this forum: No registered users and 1 guest