zero order reaction
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zero order reaction
Why is it a zero order reaction with slope -k if the straight line fits to the data?
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Re: zero order reaction
The slope is -k because the integrated rate law for zero order is
-kt + [A]o = [A]
similar to the straight line y= mx + b
[A] = -kt + [A]o
-kt + [A]o = [A]
similar to the straight line y= mx + b
[A] = -kt + [A]o
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Re: zero order reaction
The integrated rate for a first order reaction is A= -kt + Ao which is in the form of a linear equation where -k is the slope.
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Re: zero order reaction
A zero order equation integrated gives a first order equation, which when graphed, gives a straight line, as opposed to a second order equation, like something with x^2, that gives a parabola.
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