Homework Problem 7.1

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Homework Problem 7.1

Postby Kennedi2J » Sun Mar 08, 2020 8:38 pm

This problem asks to distinguish which product has the larger activation energy and the only information given besides the molecule is temperature. Since temperature increases k and speeds up the run shouldn't the product with the lower temperature have the larger activation energy? The answer says the opposite, can anyone explain this?

Juliet Stephenson 4E
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Joined: Wed Sep 18, 2019 12:21 am

Re: Homework Problem 7.1

Postby Juliet Stephenson 4E » Sun Mar 08, 2020 8:48 pm

At the lower temperature, when kinetics dominates, CH3CHBrCH=CH2 is in a higher quantity. At the higher temperature, when thermodynamics dominates, CH3CH=CHCH2Br is in a higher quantity. The product formed at lower temperatures will have the lower activation energy, since it is forming as a result of only the influence of kinetics. Therefore, the product formed at the higher temp will have the higher activation energy. Adding heat permits this product to form at a faster rate than the other. Hope this helped!

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