Course Reader 2nd Order Rxn


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004643111
Posts: 14
Joined: Fri Sep 25, 2015 3:00 am

Course Reader 2nd Order Rxn

Postby 004643111 » Sun Feb 14, 2016 3:29 am

In the course reader on page 67, when integrating, how does -(d[A])/([A]^2)=kdt turn into positive (1/[A])=kt+b? I understand the integration but not why the negative disappears.

Edwin Ng 1G
Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

Re: Course Reader 2nd Order Rxn

Postby Edwin Ng 1G » Sun Feb 14, 2016 11:33 am

When you integrate (1/[A]2) it becomes (-1/[A]), and so the two negatives cancel

Bryan Trieu 1F
Posts: 11
Joined: Fri Sep 25, 2015 3:00 am

Re: Course Reader 2nd Order Rxn

Postby Bryan Trieu 1F » Sun Feb 14, 2016 4:09 pm

Yes, the integration is no longer based off of natural log rules, just basic exponential integration. I believe that 1st order reactions depend on natural logs when integrating but the others are based off of basic exponential integration .


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