## Slopes of the orders

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

BeejenPatel_1B
Posts: 10
Joined: Wed Nov 18, 2015 3:00 am

### Slopes of the orders

Can there ever be a slope of 0? So the slope would just be --- instead of \ or /

Cindy Chen_2I
Posts: 43
Joined: Wed Nov 18, 2015 3:00 am

### Re: Slopes of the orders

The slope would be 0 when the concentration of something remain constant. So that would either mean this reaction is not occurring or that the system has reached equilibrium.

Cindy Chen_2I
Posts: 43
Joined: Wed Nov 18, 2015 3:00 am

### Re: Slopes of the orders

And I was assuming you mean when we plot concentration against time. If the reaction is a zero-order reaction, the slope of rate against time can also be 0.