## Rate law

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Markus Min 2I
Posts: 16
Joined: Fri Sep 25, 2015 3:00 am

### Rate law

When using the rate law, are the exponents of the different reactants always equal to the stoichiometric coefficients of these reactants?

i.e. for 2A -> B, will n in rate = k[A]^n always be 2?

LinaLi2E
Posts: 22
Joined: Fri Sep 25, 2015 3:00 am

### Re: Rate law

No, the exponent--order--does not always equal the stoichoimetric coefficient. For 2A->B, the rate=k[A]^n where n=2 because rate=k[A][A]. It is not because there are two moles of A but because there are two reactants that happen to be the same.