Rate law

[Markus Min 2I]

When using the rate law, are the exponents of the different reactants always equal to the stoichiometric coefficients of these reactants?

i.e. for 2A -> B, will n in rate = k[A]^n always be 2?

[LinaLi2E]

No, the exponent--order--does not always equal the stoichoimetric coefficient. For 2A->B, the rate=k[A]^n where n=2 because rate=k[A][A]. It is not because there are two moles of A but because there are two reactants that happen to be the same.