Week 9&10 Achieve #5

[andrea guzman 1F]

What will be the initial rate be if [A] is tripled and [B] is halved?
I know that because [A] is tripled and its first order then the initial rate will be multiplied by 3 but for [B] which is second order is the exponent divided by 2? to then have a factor of k(3)(1)?

[Aditya Narashim 1K]

The resulting concentration for be should be 1/4 not 1. This is due to it being second order.

[Denise Mora 1C]

The initial concentration of [B] should be the initial rate *3*1/4. It is multiplied by 1/4 because the concentration of a second‑order reactant is halved, so the reaction rate changes by a factor of (1/2)^2=1/4.