rate law

[Franca Park 3J]

since Rate = -(1/a)d[R]/dt = k[R]^n
if you had a reaction and the coefficient of the reactant (for example NO2) was something other than 1 (such as 2) would the rate law look like this: rate=(-1/2)[NO2]^n

[804584179]

Yes, coefficient goes as exponent of coefficient