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Overall Order of a Reaction

Posted: Wed Feb 22, 2017 11:27 pm
by keyanabogan 2J
On page 621, it shows that the reaction of 2O3(g)->3O2(g) has a rate law of k([O3]^2/[O2]). I don't understand what happens to the coefficient of O2 in the rate law equation. Why doesn't O2 have a superscript of 3?

Re: Overall Order of a Reaction

Posted: Thu Feb 23, 2017 1:15 pm
by Josh Ku 3H
On page 621 the rate law is experimentally determined. You cannot determine the rate law from the coefficients in the overall reaction, only from elementary steps as seen on page 70 in the course reader.

Hope this helps

Re: Overall Order of a Reaction

Posted: Sun Feb 26, 2017 7:40 pm
by samuelkharpatin2b
In order to derive a rate law, you must compare experimental data or pay attention to the slow step in a given mechanism. There is no formula or anything like that where you can simply find the rate law without experimental data or the mechanism.