15.3(c)

Jasmine Botello 2F · Postby **Jasmine Botello 2F** » Thu Feb 22, 2018 7:17 pm

For this part of the question, it asks "What is the unique rate of the reaction" and I am not really sure what it is asking me to find..?

Kate Zeile 2D · Postby **Kate Zeile 2D** » Thu Feb 22, 2018 8:46 pm

In the textbook, the unique average reaction rate for reaction $aA+bB\rightarrow cC+dD$ is :
$-\frac{1}{a}\frac{\Delta [A]}{\Delta t} = -\frac{1}{b}\frac{\Delta [B]}{\Delta t} = \frac{1}{c}\frac{\Delta [C]}{\Delta t} = \frac{1}{d}\frac{\Delta [D]}{\Delta t}$
In problem 15.3, the unique rate of the reaction refers to the unique rate of the reaction of 2NO₂ (the reactant in the equation). Therefore, the unique rate of the reaction would be - $\frac{1}{2}\frac{\Delta [NO2]}{\Delta t}$ . You would divide by 2 since the coefficient of NO₂ is 2 in the given reaction.

Kate Zeile 2D · Postby **Kate Zeile 2D** » Wed Feb 28, 2018 7:18 am

Sorry I would like to make a correction. The unique rate of the reaction refers to any one of the parts of this equation: $-\frac{1}{a}\frac{\Delta [A]}{\Delta t}=-\frac{1}{b}\frac{\Delta [B]}{\Delta t}=\frac{1}{c}\frac{\Delta [C]}{\Delta t}=\frac{1}{d}\frac{\Delta [D]}{\Delta t}$ ; all are equal. However, since the concentration of NO₂ is given in the problem, we use that part. The unique rate of the reaction is the concentration that is given for one part of the chemical equation divided by its coefficient (and a negative if it is a reactant).

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15.3(c)

15.3(c)

Re: 15.3(c)

Re: 15.3(c)

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