Can someone explain why -d[NO2]/dt=d[NO]/dt=2 d[O2]/dt
I'm confused about the 2 before the d[O2]/dt
Rate of Reaction
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Re: Rate of Reaction
In the chemical equation, the stoichiometric coefficients show that for every mol of O2 formed there are 2 mol of NO and NO2, so it O2 is forming half as fast. Thus, its rate would have to be doubled to equal the rate of NO being formed and NO2 being broken down.
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Re: Rate of Reaction
The 2 is there due to the ratio of the coefficients between the reactants and the products.
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Re: Rate of Reaction
Since the stoichiometric coefficients are 2 for NO2 and 1 for O2, the rate of O2 production will be half of that of NO2 depletion.
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Re: Rate of Reaction
you just need to pay attention to the coefficients, and since o2 is half, theres half as much made
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