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Rate of Reaction

Posted: Sun Feb 25, 2018 11:42 pm
by Vanessa Romero-Campos 2B
Can someone explain why -d[NO2]/dt=d[NO]/dt=2 d[O2]/dt
I'm confused about the 2 before the d[O2]/dt

Re: Rate of Reaction

Posted: Sun Feb 25, 2018 11:46 pm
by Jessica Patzlaff 1A
In the chemical equation, the stoichiometric coefficients show that for every mol of O2 formed there are 2 mol of NO and NO2, so it O2 is forming half as fast. Thus, its rate would have to be doubled to equal the rate of NO being formed and NO2 being broken down.

Re: Rate of Reaction

Posted: Sun Feb 25, 2018 11:46 pm
by Timothy Kim 1B
The 2 is there due to the ratio of the coefficients between the reactants and the products.

Re: Rate of Reaction

Posted: Sun Feb 25, 2018 11:51 pm
by AnuPanneerselvam1H
Since the stoichiometric coefficients are 2 for NO2 and 1 for O2, the rate of O2 production will be half of that of NO2 depletion.

Re: Rate of Reaction

Posted: Mon Feb 26, 2018 9:39 am
by Kayla Tchorz-Dis 1F
you just need to pay attention to the coefficients, and since o2 is half, theres half as much made