15.17


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Mia Navarro 1D
Posts: 52
Joined: Fri Sep 29, 2017 7:04 am

15.17

Postby Mia Navarro 1D » Mon Feb 26, 2018 11:35 pm

Why, when solving for the rate, is [B] squared?

Caroline LaPlaca
Posts: 30
Joined: Sat Jul 22, 2017 3:01 am

Re: 15.17

Postby Caroline LaPlaca » Tue Feb 27, 2018 1:25 am

No, cause its not like the K concentration thing.

Johann Park 2B
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Re: 15.17

Postby Johann Park 2B » Tue Feb 27, 2018 10:33 am

With respect to [B], the reaction is second-order. You use the different values for the rates and concentrations to solve for the exponents (x, y, z) on the concentrations.

OliviaShearin2E
Posts: 37
Joined: Fri Sep 29, 2017 7:05 am

Re: 15.17

Postby OliviaShearin2E » Tue Feb 27, 2018 5:36 pm

Johann is right but to be clearer, first order in B means that the rate is proportional to , second order in B means that the rate is proportional to . and third order in B means that the rate is proportional to .

Sandhya Rajkumar 1C
Posts: 50
Joined: Fri Jun 23, 2017 11:40 am

Re: 15.17

Postby Sandhya Rajkumar 1C » Tue Feb 27, 2018 10:03 pm

The reaction is second order with respect to B because when the amount of B is doubled (increased by a factor of 2), the rate increases by a factor of 4, so instead of it being a 1:1 ratio, which would make it first order, it's a 1:2 ratio, which makes it second order.


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