## 15.85

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Maria1E
Posts: 61
Joined: Sat Jul 22, 2017 3:01 am

### 15.85

Question: The following rate laws were each derived from an elementary reaction. In each case, write the chemical equation for the reaction, determine its molecularity, and draw a proposed structure for the activated complex.
a) Rate = k[CH3CHO] (products are CH3 and CHO)
b) Rate = k[I]^2[Ar] (products are I2 and Ar; the role of Ar is to remove energy as the product forms)
c) Rate = k[O2][NO] (products are NO2 and O)

I am confused as to how to write the proposed structures. The solutions written in the solution manual are:
a) [CH3..........CHO]
b) [I..........I..........Ar]
c) [O..........O..........NO]
Can someone explain how these answers were constructed (particularly part C)?

Alyssa Parry Disc 1H
Posts: 53
Joined: Sat Jul 22, 2017 3:01 am

### Re: 15.85

Can you clarify what you mean by how the answers are constructed?

Maria1E
Posts: 61
Joined: Sat Jul 22, 2017 3:01 am

### Re: 15.85

I am confused on how to draw proposed structures overall.

April P 1C
Posts: 38
Joined: Thu Jan 12, 2017 3:01 am

### Re: 15.85

I am also confused. Also, does anyone know if we will have to write the proposed structures for the exam?