## Deriving integrated rate laws

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Miranda 1J
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am

### Deriving integrated rate laws

Do we need to know how to derive the rate laws in the y=mx+c form or do we only need to know the integrated form of the equation?

Isita Tripathi 2E
Posts: 52
Joined: Sat Jul 22, 2017 3:00 am
Been upvoted: 1 time

### Re: Deriving integrated rate laws

You need to know the differential rate laws (rate in terms of concentration) and the integrated rate laws (rate in terms of conc+time). The derivations are really helpful to conceptually understand going from the differential to integrated, but both are provided on the constants and equations sheets, so you don't need to memorize the derivations.

Justin Chang 2K
Posts: 53
Joined: Fri Sep 29, 2017 7:04 am

### Re: Deriving integrated rate laws

Yeah, since both differential and integrated rate laws are provided on the equations, I would just worry about memorizing which equation relates to zero order, first order, and second order.

Magdalena Palavecino 1A
Posts: 54
Joined: Fri Sep 29, 2017 7:04 am

### Re: Deriving integrated rate laws

Does the y=mx+b form refer to anything else than the graphs we looked at in class?

404995677
Posts: 82
Joined: Fri Sep 29, 2017 7:07 am

### Re: Deriving integrated rate laws

Magdalena Palavecino 1A wrote:Does the y=mx+b form refer to anything else than the graphs we looked at in class?

No i dont believe so, the y=mx+b is just to help visualize the graphs better