Rate Law dependent on Reactants  [ENDORSED]


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Jessica Yang 1J
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Rate Law dependent on Reactants

Postby Jessica Yang 1J » Thu Mar 01, 2018 6:07 pm

Why is the rate law only include the concentration of reactants along with k? For example, all of the rate laws in table 15.1

Thanks!

Jasmine Wu 1L
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Re: Rate Law dependent on Reactants

Postby Jasmine Wu 1L » Thu Mar 01, 2018 6:26 pm

For a chemical reaction aA + bB cC + dD the formula for rate is k[A]a[B]b, where k is the rate constant, [A] is the concentration of reactant A, and [B] is the concentration of reactant B. Each reaction has its own unique rate law and rate constant, so Table 15.1 is just generalizing for you what the rate law would be when given a reaction.

Salma Quintanilla 1J
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Re: Rate Law dependent on Reactants

Postby Salma Quintanilla 1J » Thu Mar 01, 2018 9:18 pm

The rate constant (k) depends on the temperate and activation energy.

Magdalena Palavecino 1A
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Re: Rate Law dependent on Reactants

Postby Magdalena Palavecino 1A » Sat Mar 03, 2018 12:47 pm

How would we take into account temperature and activation energy when calculating k? Also, I'm confused about all the meanings we have given K in this class. Is k here the rate or the equilibrium constant?

Chem_Mod
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Re: Rate Law dependent on Reactants  [ENDORSED]

Postby Chem_Mod » Mon Mar 05, 2018 2:04 pm

k is the rate constant, while K is the equilibrium constant generally. You don't need to factor the temperature or activation energy into an calculations of k, it is just a conceptual fact that you should know. There is no mathematical way to determine reaction rates besides experimenting.


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