Why is the rate law only include the concentration of reactants along with k? For example, all of the rate laws in table 15.1
Thanks!
Rate Law dependent on Reactants [ENDORSED]
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 55
- Joined: Thu Jul 27, 2017 2:00 am
- Been upvoted: 1 time
Re: Rate Law dependent on Reactants
For a chemical reaction aA + bB
cC + dD the formula for rate is k[A]a[B]b, where k is the rate constant, [A] is the concentration of reactant A, and [B] is the concentration of reactant B. Each reaction has its own unique rate law and rate constant, so Table 15.1 is just generalizing for you what the rate law would be when given a reaction.
-
- Posts: 29
- Joined: Wed Nov 23, 2016 3:02 am
Re: Rate Law dependent on Reactants
The rate constant (k) depends on the temperate and activation energy.
-
- Posts: 54
- Joined: Fri Sep 29, 2017 6:04 am
Re: Rate Law dependent on Reactants
How would we take into account temperature and activation energy when calculating k? Also, I'm confused about all the meanings we have given K in this class. Is k here the rate or the equilibrium constant?
Re: Rate Law dependent on Reactants [ENDORSED]
k is the rate constant, while K is the equilibrium constant generally. You don't need to factor the temperature or activation energy into an calculations of k, it is just a conceptual fact that you should know. There is no mathematical way to determine reaction rates besides experimenting.
Who is online
Users browsing this forum: No registered users and 1 guest