## 15.25 part b

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Paula Dowdell 1F
Posts: 72
Joined: Tue Nov 15, 2016 3:00 am

### 15.25 part b

Hi,
In part (b) why is it that 3.5h is used for the value of "t" instead of 2s? I thought we would use 2s because the question asked "(b) If [N2O5]0 = 0.0567 mol L-1, what will be the concentration of N2O5 after 2.0 s? "
The work in the solutions manual is as follows:
[N2O5]=0.0567molL-1 x e^-(3.7x10^-5 s-1)(1.3x10^-4 s)= 3.5x10^-2 mol/L
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Maeve Gallagher 1J
Posts: 56
Joined: Fri Sep 29, 2017 7:07 am

### Re: 15.25 part b

I think you may have misread the question, part b reads "If [N2O5]0 = 0.0567 mol L-1, what will be the concentration of N2O5 after 3.5h?" so therefore you use 3.5 hours converted into seconds for your time.