## higher order rate laws

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Belle Calforda3f
Posts: 67
Joined: Fri Sep 29, 2017 7:07 am

### higher order rate laws

would Lavelle ever expect us to derive integrated rate laws greater than second order?

Danah Albaaj 1I
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

### Re: higher order rate laws

No, because as he has mentioned many times. We won't really be be involving ourselves with reactions that are more than second order due to their complexity.