15.17

[itzeelpadillaDis1A]

We calculate the orders for A and B but not C, why is that?

[Alvin Tran 2E]

If you compare experiments 1 and 4 (where the concentrations of A and B stay the same), you see that the initial concentration of C changes but the initial rate doesn't change. Therefore, the reaction is zero order with respect to C.

[Adrian Lim 1G]

Because C is independent of the rate, we consider it as zero order. Therefore, we would not include it in our rate of reaction equation

[Beza Ayalew 1I]

Because C is the zeroth order, it's concentration does not change the rate at all, so it's not added to the rate law because the concentration of C doesn't affect the rate. However, I'm not exactly sure if you would be deducted points for including [C]^0 on a test in the rate law equation