## Pg. 621 of textbook

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

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Kellina Tran 2I
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### Pg. 621 of textbook

For the example regarding the oxidation of sulfur dioxide to sulfur trioxide in the presence of platinum, the textbook says that the reaction slows down as the concentration of SO3 increases. However, shouldn’t the reaction speed up because the fractional order of SO3 is 1/2?

Hyein Cha 2I
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### Re: Pg. 621 of textbook

Reaction would slow down as concentration of SO3 builds up because it is in the denominator.

Plug some numbers in. Let's say the concentration of SO3 is 4, then the denominator is 2. If concentration increases to 9, then square root of 9 is 3. The point is, no matter what the exponent may be, if it's on the denominator, then increasing its concentration will decrease the rate overall.

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