Problem 15.37


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allyz1F
Posts: 58
Joined: Sat Jul 22, 2017 3:00 am

Problem 15.37

Postby allyz1F » Wed Mar 07, 2018 10:38 am

This problem asks for the time needed for SO2Cl2 concentration to decrease to 10% of the initial concentration. In the answer it says t= ln(SO2Cl2 initial/SO2Cl2 ) / k is equal to ln10/k. Why is this?

Joshua Xian 1D
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Re: Problem 15.37

Postby Joshua Xian 1D » Wed Mar 07, 2018 11:02 am

Since final concentration is 10% of the initial, dividing initial by final would result in 10. Therefore, you get ln(10)/k.

Lauren Seidl 1D
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Joined: Fri Sep 29, 2017 7:06 am

Re: Problem 15.37

Postby Lauren Seidl 1D » Wed Mar 07, 2018 11:10 am

Because they divide initial concentration by final concentration, you get a value of 10 in the ln and would therefore set ln(10) = k*t. If you divided final concentration by initial concentration instead, you would get a value of 0.1 in the ln, but you would have to set ln(0.1) = - k*t according to the equation ln[A] = -k*t + ln[A]0. They just flipped it around so that positive k*t = ln([A]0/[A]).

Shanmitha Arun 1L
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Re: Problem 15.37

Postby Shanmitha Arun 1L » Wed Mar 07, 2018 11:48 am

You would do ln(1/0.1) which is the same as ln(10).


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