Coefficients

[Xihui Yin 1I]

Given that the formulas for the various zero first second order reactions assume that the coefficient of the reactant is 1, for cases where the coefficient is not 1, do you have to adjust the formula by the coefficient accordingly?


E.g. aA->bB for a first order reaction. Rate=a•k[A], so differential rate would be d[A]/[A]=-a•k•dt, integrated rate would be ln[A]=-a•kt+ln[A]° and half-life would be ln2/(a•k)?

[Katherine Jordak 1H]

No you wouldn't. I think the equations given are used as so regardless of the coefficients in the reaction equation.

[404995677]

I had the same question because in the page in Lavelle's website (https://lavelle.chem.ucla.edu/wp-conten ... amples.pdf) it says "*In the following derivations of the three integrated rate laws, we assume
the stoichiometric coefficient "a" in front of reactant A is 1." Maybe in class we will only be working with equations where the coefficients are equal to 1?

[Xihui Yin 1I]

I had the same question because in the page in Lavelle's website (https://lavelle.chem.ucla.edu/wp-conten ... amples.pdf) it says "*In the following derivations of the three integrated rate laws, we assume
the stoichiometric coefficient "a" in front of reactant A is 1." Maybe in class we will only be working with equations where the coefficients are equal to 1?

That shouldn't be the case bc the homework questions have coefficients>=1

[Connor Kelligrew 2D]

I believe that these coefficients do not affect how we write the rate laws for first and second order reactions.

It would affect the unique rate of the reaction and finding the rates of consumption/production for one reactant/product in terms of another reactant/product's rate of consumption/production

[404995677]

I believe that these coefficients do not affect how we write the rate laws for first and second order reactions.

It would affect the unique rate of the reaction and finding the rates of consumption/production for one reactant/product in terms of another reactant/product's rate of consumption/production

But isn't the Differential Rate Law, which we use to get the Integrated Rate Law, determined by the unique rates?