15.17


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Lucia H 2L
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15.17

Postby Lucia H 2L » Thu Mar 08, 2018 8:11 pm

The problem asks you you to look at a table and determine the order for each reactant.

When the concentration of A is 10, rate = 2.0
when the concentration of A is 20, rate = 4.0 (all else equal)

Since 2 to 4 could be doubling or squaring, can you tell from this much information what the order is of A? Is there another part of the problem that gives away more?

Gurvardaan Bal1L
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Re: 15.17

Postby Gurvardaan Bal1L » Thu Mar 08, 2018 8:23 pm

In this case when you double the amount of A you double the reaction rate so that is not squaring. It would be squaring if you doubled the concentration of A and then the reaction rate quadrupled, or if you tripled the concentration and the rate increased by a factor of 9.

Based off this you would be able to know that the order is 1 for A

Juanyi Tan 2K
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Re: 15.17

Postby Juanyi Tan 2K » Thu Mar 08, 2018 8:32 pm

In this question, you can find out the order for B and C first. After you know their order, you can then compare results from different experiment so that the reaction rate is not squaring when the concentration of A doubles. For example, you can compare experiment 1 and experiment 3 after you determine the order for B is 2 and order for C is 0.


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