## HW 15.55

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Katie Blann 1E
Posts: 29
Joined: Tue Nov 15, 2016 3:00 am

### HW 15.55

Why is part A of this problem true?

lindsay lathrop 2C
Posts: 29
Joined: Sat Jul 22, 2017 3:00 am

### Re: HW 15.55

This comes down to the equation for equillibrium constant K. $K=\frac{k}{k{}'}$ Where k is the rate constant for the forward reaction and k' is the rate constant for the reverse reaction. When k is larger it creates an overall larger K. However, if k' was larger, since its in the denominator it would cause the overall K to become smaller.