## Rate Law where a concentration is to a negative power

$aR \to bP, Rate = -\frac{1}{a} \frac{d[R]}{dt} = \frac{1}{b}\frac{d[P]}{dt}$

Mary Becerra 2D
Posts: 53
Joined: Fri Sep 29, 2017 7:06 am

### Rate Law where a concentration is to a negative power

When a rate law = k*([A]^3/[B]^-1), what does the negative power mean? I was thinking it was an inhibitor of some kind since it reduces the order of the reaction?

David Minasyan 1C
Posts: 54
Joined: Thu Jul 13, 2017 3:00 am

### Re: Rate Law where a concentration is to a negative power

The negative power brings the concentration of that species to the bottom of the rate so having more of it would lower the rate. So yeah it's much like an inhibitor.

Troy Tavangar 1I
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

### Re: Rate Law where a concentration is to a negative power

It is like an inhibitor since it brings it underneath and makes value decrease.