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Postby Meachelle_Lum_1I » Wed Mar 06, 2019 11:30 pm

For 15.3 part a when finding the reaction rate of NO2, how come we don't divide by 2, the coefficient of NO2?

Jerome Mercado 2J
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Re: 15.3

Postby Jerome Mercado 2J » Wed Mar 06, 2019 11:45 pm

Reaction rate depends on the duration of the NO2 not the coefficient of the substance. It would be the change in concentration over the time duration of a reaction thus it would be divided by 20s instead of 2.

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Re: 15.3

Postby Kate_Santoso_4F » Wed Mar 06, 2019 11:49 pm

The rate of reaction of NO2 can be found by the change in concentration of NO2 divided by the change in time. We are given the initial and final concentrations of NO2 in the problem (450 mmol/L to 320 mmol/L) and the change in time (20s). Therefore, the rate of reaction of NO2 is -(320 mmol/L - 450 mmol/L)/20s = 6.5 mmol/L*s or 6.5*10^-3 mol/L*s.

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