15.5


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josephyim1L
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

15.5

Postby josephyim1L » Thu Mar 07, 2019 11:01 pm

Can someone explain:

15.5 Ethene is a minor but important component of natural gas, and its combustion has been thoroughly studied. At a certain temperature and pressure, the unique rate of the combustion reaction C2H4(g) + 3 O2(g) 2 CO2(g) 2 H2O(g) is
0.44 mol/L/s. (a) What is the rate at which oxygen reacts? (b) What is the rate of formation of water molecules?

Chem_Mod
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Re: 15.5

Postby Chem_Mod » Fri Mar 08, 2019 1:41 am

Here's a hint:
Screen Shot 2019-03-08 at 1.40.32 AM.png

Brandon Mo 4K
Posts: 70
Joined: Fri Sep 28, 2018 12:15 am

Re: 15.5

Postby Brandon Mo 4K » Fri Mar 08, 2019 5:37 am

You can find the unique rate expression of the each reactant and product, then set it equal to the unique rate.

For example:
(-1/3)(d[O2]/dt) = -(0.44 mol/Ls)


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