12 posts • Page 1 of 1
You can also look at the rate values(if given) and compare--the bigger the rate, the faster it is. The rate constant, k, is directly proportional to the rate, so the bigger the k, the bigger the rate=faster reaction. The rate determining step, being the slowest, should usually have the smallest k and, therefore, rate.
If you know that the reaction is a pre-equilibrium reaction, then the second step will be the slow one. That first step is going to be a fast reaction and it is considered to be at equilibrium where there is a bottle necking effect and that leads into your second step which is going to be the rate determining step. If the problem is not at equilibrium, then you they must give you the reaction rate or they must tell you which is slow and which is fast.
Who is online
Users browsing this forum: No registered users and 2 guests